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-0.5x^2+2x-2=2
We move all terms to the left:
-0.5x^2+2x-2-(2)=0
We add all the numbers together, and all the variables
-0.5x^2+2x-4=0
a = -0.5; b = 2; c = -4;
Δ = b2-4ac
Δ = 22-4·(-0.5)·(-4)
Δ = -4
Delta is less than zero, so there is no solution for the equation
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